Answer:see explanationStep-by-step explanation:Given6a² - a - 5 = 0Consider the factors of the product of the a² term and the constant term which sum to give the coefficient of the a- term.product = 6 × - 5 = - 30 and sum = - 1The factors are - 6 and + 5Use these factors to split the a- term6a² - 6a + 5a - 5 = 0 ( factor the first/second and third/fourth terms )6a(a - 1) + 5(a - 1) = 0 ← factor out (a - 1) from each term(a - 1)(6a + 5) = 0Equate each factor to zero and solve for aa - 1 = 0 ⇒ a = 16a + 5 = 0 ⇒ 6a = - 5 ⇒ a = - [tex]\frac{5}{6}[/tex]Solution set = { 1, - [tex]\frac{5}{6}[/tex] }