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For what values of y does 125=(1/25)^y-1
4 months ago
Q:
For what values of y does 125=(1/25)^y-1
Accepted Solution
A:
[tex]125 = \frac{1}{125} {}^{y - 1} \\ 125 = ( {5}^{ - 2} ) {}^{y - 1} \\ \\ {5}^{3} = {5}^{2 - 2y} \\ 3 = 2 - 2y \\ - 0.5 = y[/tex]